will give medals A square pyramid has a base area of 36 ft2. The pyramid’s total surface area is 144 ft2. What is the area of each triangular face? A. 108 ft2 B. 54 ft2 C. 36 ft2 D. 27 ft2
you subtract 144-36=108 than divide 108 with 4 and get 27ft2
it's simple you have Base Surface Area .... and hence you get side length since B = a2
Now you have got 'Total Surface Area of a square pyramid' .... and side length (a)
thru this you get h (height)
A = a(a + √(a2 + 4h2))
actual not really they give you the surface area so you just subtract it with the base and divide by 4 cause a pyramid
and nw since you got 'a' and 'h'... you get lateral surface area L = a√(a2 + 4h2)
and finally divide it by 4 ...and you get area of each triangular face
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