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Mathematics 9 Online
OpenStudy (anonymous):

Find BC

OpenStudy (anonymous):

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OpenStudy (anonymous):

@ganeshie8 would we use the same equation form the previous triangle

OpenStudy (anonymous):

BC^2=9^2+14^2-2*9*14*cos(17)

OpenStudy (anonymous):

would this be the equation to solve for BC

OpenStudy (colouringme):

yes :)

OpenStudy (anonymous):

okay thanks

OpenStudy (anonymous):

BC=6

OpenStudy (anonymous):

BC^2=36 and we square each side so BC=6

OpenStudy (colouringme):

yes! :D

OpenStudy (anonymous):

thanks

OpenStudy (colouringme):

;) no problem

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