Question

help please

Answer 1

Divide. Assume the denominator does not equal zero.
(18x^5y^3 + 6x^2y^4 + 24x6y) ÷ 3xy

Answer 2

hey

Answer 3

omg hey gurl

Answer 4

ok so the problem

Answer 5

\[\frac{18x^5y^3 + 6x^2y^4 + 24x6y}{3xy}\]You can do this
\[\frac{18x^5y^3}{3xy} + \frac{6x^2y^4}{3xy} + \frac{24x6y}{3xy}\]

Answer 6

\[\frac{ 18x^5y^3 }{ 3xy }= 6x^4y^2\]
heres the first part do u know how i did it

Answer 7

yes u divided :P