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If y varies directly as x, and y = 15 as x = -3, find y for the x-value of 6
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\(\bf \begin{array}{cccllll} \textit{something }&\textit{varies directly to }&\textit{something else}\\ \quad \\ \textit{something }&={\color{red}{ \textit{some value }}}&\textit{something else}\\ \quad \\ y&={\color{red}{ n}}&x&\implies y={\color{red}{ n}}x \end{array}\\ \quad \\ y = 15 \qquad x = -3\implies 15={\color{red}{ n}}(-3)\) solve for "n", or "constant of variation" once you find "n", plug in its value in the original equation to find "y" when x = 6, well, just set "x" to 6 and solve for "y"
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