Will give medal! :) Please help Jose is paying for a six dollar meal using bills in his wallet. He has four one dollar bills, three five dollar bills, and two ten dollar bills. If he selects two bills at random, one at a time from his wallet, what is the probability that he will choose a one dollar bill and a five dollar bill to pay for the meal? Show your work.
im sorry i dont know the proper way to calculate probability
ok...
The total number of bills is 9, correct? There is a 4/9 chance of Jose picking a one dollar bill to pay for the meal. Once he picks the one-dollar bill, there is a 3/8 chance that he picks a five dollar bill. 4/9 x 3/8 =...
hold on...
0.16
Er, yes, but probabilities are usually expressed in fractions. so that would be 1/6.
ok...
You can see that even if Jose picks the five-dollar bill first (3/9 chance) and the one dollar bill second (4/8) you get the same probablity.
Do you understand?
pretty much... so the probability is 1/6
Yup. :)
is that all?
Yes
thank you so much!!! :)
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