An advertisement for a word-processing class claims that students who complete the class will, on average, be able to type 60 words per minute (wpm) with a standard deviation of 6 wpm. At the end of the class, 49 students are tested and their mean score is 58.5 wpm.
An advertisement for a word-processing class claims that students who complete the class will, on average, be able to type 60 words per minute (wpm) with a standard deviation of 6 wpm. We're concerned that students aren't performing as well as advertised. At the end of the class we test 49 students and conduct a one-sided hypothe

Question

An advertisement for a word-processing class claims that students who complete the class will, on average, be able to type 60 words per minute (wpm) with a standard deviation of 6 wpm. At the end of the class, 49 students are tested and their mean score is 58.5 wpm. 
An advertisement for a word-processing class claims that students who complete the class will, on average, be able to type 60 words per minute (wpm) with a standard deviation of 6 wpm. We're concerned that students aren't performing as well as advertised. At the end of the class we test 49 students and conduct a one-sided hypothe

anonymous · Answer

please finish the question and i will try and answering!

anonymous · Answer

hypothesis test at the .05 level of significance. This means that the hypothesis will be rejected if the mean wpm is less than 58.6. Suppose, in reality, the true mean for graduates is 58 wpm with a standard deviation of 5 wpm.

A. What's the probability of a Type II error? 



B. What's the power of the test if the true population mean is 58 wpm? Draw a diagram of the sampling distribution for the sample mean, showing the area that represents the power of the test and the area that represents the probability of a Type II error.

anonymous · Answer

@Thee121