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how to differentiate : y = sqrt[ (1+tan x) / ( 1- tan x) ]
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\[\sqrt{\dfrac{1+tanx}{1-tanx}}\] right?
yes right
Let the sqrt aside, just calculate the terms inside, turn tan to sin/cos and simplify it what do you have?
tan = sin/cos
\[\sqrt{\dfrac{\cos x + \sin x}{\cos x-\sin x}}\]
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