Question

:)

Answer 1

b

Answer 2

:D

Answer 3

but how ?

Answer 4

@ganeshie8

Answer 5

@hoblos

Answer 6

what is this

Answer 7

Homework.. I don't understand why you said b

Answer 8

\[ax^2 + bx + c = 0\]\[\Large x = \frac{ -b \pm \sqrt{b ^{2} - 4ac} }{ 2a }\]

Answer 9

ans is B. general quadratic equation is \[ax^{2} + bx +c = 0 \]

for the given equation we convert the given equation into this form and find the value of a, b , and c.

now we find x by this formula.

\[x= \frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]

Answer 10

in which class you are

Answer 11

math

Answer 12

class not subject