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f(x)=x^2 -1 / x^3 At what opints, if any, does the function assume local extrem values?
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differentiate the function and put it equal to zero solve for x u'll find some value it'll be extrem value.
what you mean ?!
I differentiate before
you know about differentiation???
and I get X value
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these values are extreme values!!
x value x=sqrt(3) and x= - sqrt(3)
I want local extrem values
how I can get ?
the values you found ,check for local extrem values by this local maximum at c if and only if f(x) f(c) for all x in some open interval containing c. local minimum at c if and only if f(c) f(x) for all x in some open interval containing c.
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f(x)<f(c) f(x)>f(c)
what mean f(c)??
c is the value what you got
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