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Use FOIL to multiply the two binomials. (b + 3)(b + 9) A. b^2 + 12b + 27 B. b^2 + 6b – 27 C. b^2 – 6b – 27 D. b^2 – 27 i got C is that correct?
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b^2+9b+3b+27 =b^2+12b+27
ohh ok so its A?
Yes
\[\large(\overbrace{\overbrace{\color{orange}a +\underbrace{\color{cornflowerblue}b)(\color{seagreen}c}_{\text{Inside}}}^{\text{First}} +\color{brown}d}^{\text{Outside}}) =\overbrace{\color{orange}a\color{seagreen}c}^\text F +\overbrace{\color{orange}a\color{brown}d}^\text O +\underbrace{\color{cornflowerblue}b\color{seagreen}c}_\text I +\underbrace{\color{cornflowerblue}b\color{brown}d}_L\\ \large\qquad\quad \underbrace{\qquad\qquad}_{\text{Last}}\]
How did you...nice :)
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