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Which of the following is equivalent to the sum of negative 3n minus 4 for n equals 4 to 8 ?
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These are the choices: –110 –88 88 110
And this is the problem: \[\sum_{n=4}^{8} -3n -4\]
\[\sum_{n=4}^{8}-3n-4=\sum_{n=4}^{8}-3n-\sum_{n=4}^{8}4\]
So how do I proceed from here? And thank you by the way.
\[=-3\sum_{n=4}^{8}n-\sum_{n=4}^{8}4\]
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so what do I do now?
substitute
oh and the result is -110
(-3*4-4)+(-3*5-4)+(-3*6-4)+(-3*7-4)+(-3*8-4)=-110 I've done the substitution for you also
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