Question

Find values of a & b that make each set of equations true.
6=a•b^0. 32=a•b^2
24=a•b^2. 128=a•b^3

Answer 1

b^0 = 1
Therefore, a = 6
Substitute a = 6 into
24 = a x b^2
24 = 6 x b^2
24/6 = b^2
4 = b^2
sqrt(4) = b
2 = b
BUT why is 32 = a x b^2 the same as 24 = a x b^3 with the expression, are you sure that you haven't mis-typed?