Rebekah kicks a soccer ball off the ground and in the air with an initial velocity of 25 feet per second. Using the formula H(t) = -16t2 + vt + s, what is the maximum height the soccer ball reaches?

Question

anonymous · Answer

assuming that it goes straight up in the air, then $s=0$ and $v=25$  making your equation 
$$h(t)=-16t^2+25t$$ 
max is the second coordinate of the vertex
the first coordinate is $-\frac{b}{2a}=-\frac{25}{2\times (-16)}=\frac{25}{32}$
plug that in for $t$ and see what you get