Question

x = c tan t and y = c cot t find dy/dx ( ans given : - c^2/x^2 , I got - cot ^2 (t) or - y^2/c^2 , which is correct?)

Answer 1

both are right

Answer 2

since, (tant) * (cot t) = 1
that gives : (x/c)(y/c) = 1

xy = c^2

Answer 3

u can jump from x to y or vice versa using above relation !

Answer 4

thanks @ganeshie8