Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

4^(1+2x)=64

OpenStudy (shamim):

do u wanna know the value of x?

OpenStudy (anonymous):

Yeah, I'm supposed to solve the equation and check the solution

OpenStudy (zzr0ck3r):

\(4^{1+2x}=64\implies 4^{1+2x}=4^3\implies \log_4(4^{1+2x})=\log_4(4^3)\\(1+2x)\log_4(4)=3\log_4(4)\implies(1+2x)*1=3*1\implies 1+2x=3\)

OpenStudy (zzr0ck3r):

solve for x

OpenStudy (zzr0ck3r):

x=1

OpenStudy (zzr0ck3r):

64=4^3

OpenStudy (nirmalnema):

yaa sorry.. its by mistake 3=2x+1 x=1

OpenStudy (anonymous):

No worries, thanks everyone

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!