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4^(1+2x)=64
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do u wanna know the value of x?
Yeah, I'm supposed to solve the equation and check the solution
\(4^{1+2x}=64\implies 4^{1+2x}=4^3\implies \log_4(4^{1+2x})=\log_4(4^3)\\(1+2x)\log_4(4)=3\log_4(4)\implies(1+2x)*1=3*1\implies 1+2x=3\)
solve for x
x=1
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64=4^3
yaa sorry.. its by mistake 3=2x+1 x=1
No worries, thanks everyone
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