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please help Exponential and Logarithmic Equations solve each equation. Give an exact solution. 3^(4x+1)-5=22
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start by adding 5 on both sides
3^(4x+1)=27
yes, now you can take log on both sides. what do you get ?
Alternative way : write 27 as an exponent of 3 and compare the exponents
can you use draw cus im lost
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\(\Large 3^{4x+1} = 27 \\ \large \log (3^{4x+1}) = \log 27 \)
log shmog
now use the log property that \(\log a^b = b \log a\)
\[\large 3^{4x+1}=3^3\iff 4x+1=3\]
^ and there's your alternative way
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\[4x+1\log_{3}=\log_{27} \]
arg
since \(27=3^3\) you know \(4x+1=3\)
x=1/2
yeah, but did you get how ?
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yes|dw:1396271037293:dw|
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