Question

exact value of Tan(-17pi/6)

Answer 1

is it
\[
\frac{1}{\sqrt{3}}
\]

Answer 2

\[
\tan \left(-\frac{17 \pi }{6}\right)=\tan \left(\frac{\pi
}{6}-2 \pi \right)=\tan \left(+\frac{\pi
}{6}\right)=\frac{1}{\sqrt{3}}
\]