Trapezoid EFGH is graphed in quadrant IV of a coordinate grid. What series of reflections would map the trapezoid onto itself?
x-axis, y-axis, x-axis, y-axis
y = x, x-axis, y = x, x-axis
x-axis, y = x, x-axis, y = x
y-axis, x-axis, y-axis
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OpenStudy (gabylovesyou):
@ganeshie8 @hartnn
OpenStudy (anonymous):
Hmmm...
OpenStudy (anonymous):
Is there a picture of it?
OpenStudy (gabylovesyou):
no
OpenStudy (anonymous):
Oh. I'll try...
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OpenStudy (anonymous):
I'm pretty sure its the 3rd one
OpenStudy (gabylovesyou):
how ?
OpenStudy (anonymous):
Well look.
OpenStudy (anonymous):
Hold on..
OpenStudy (anonymous):
Let me find a graph so its easier...
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OpenStudy (gabylovesyou):
ok
OpenStudy (anonymous):
OK here it is
OpenStudy (gabylovesyou):
ok
OpenStudy (anonymous):
Open it up and then read the question and all of the answers
OpenStudy (gabylovesyou):
ok.... i did
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OpenStudy (gabylovesyou):
wait but how do i do y=x ?
OpenStudy (anonymous):
look at the x and y axis
OpenStudy (compassionate):
|dw:1396284109667:dw|
OpenStudy (gabylovesyou):
ok...
OpenStudy (gabylovesyou):
and then ?
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OpenStudy (gabylovesyou):
the first answer does take the trapezoid to itself!!
OpenStudy (anonymous):
Your right. I didnt read the question correctly. Im working on the same thing, I mean I just started this today. Sorry...
OpenStudy (gabylovesyou):
its ok ! @ParthKohli is it A ? @Compassionate is it A ?