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Please help me! Given the equation 2 Square root of x minus 5= 2, solve for x and identify if it is an extraneous solution.
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\[This is the equation?:2\sqrt{x}-5=2\]
no the square root is over the X and the 5
@ifrimpanainte
\[2\sqrt{x-5}=2|^{2}=>4(x-5)=4/:4=>x-5=1=>x=6\]
thank you!
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