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Solve the equation...
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Equations?
\[\log_{a} x=2\log_{a} 3+\log_{a} 5\]
just one equation...
Sorry, I don't know those.
\(\Huge\color{blue}{ \sf log_ax=2log_a3+log_a5 }\) \(\Huge\color{blue}{ \sf log_ax=log_a3^2+log_a5 }\) \(\Huge\color{blue}{ \sf log_ax=log_a(3^2 \times 5) }\) \(\Huge\color{blue}{ \sf x=3^2 \times 5 }\) take it from there.
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If you have any questions regarding the steps, please ASK !
So x=45! Thanks, I definitely understand the steps, thank you!
You welcome!
I have one more question I need some help with, it is a little different but it uses logarithms.
I will post it and tag you.
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