Question

sin2xcosx-cos2xsinx =(sqrt3/2)

Answer 1

\[\sin 2x \cos x-\cos 2x \sin x=\frac{ \sqrt{3} }{2 }\]
\[\sin \left( 2x-x \right)=\sin60,\sin \left( 180-60 \right)\]
x=?

Answer 2

120

Answer 3

sin x=sin 60,sin 120
x=60,120