Question

loga X + loga (x-2)=loga(x+4) Help please! step by step.

Answer 1

Please pot the full question

Answer 2

well its just saying to solve the equation.

Answer 3

Log X + Log(x-2) = Log(x+4)

Rule: Log(a.b)= Log a + Log b

Therefore:

Log x.(x-2) = Log(x+4)

= Log x^2-2x = Log(x+4)

Rule: Log(a)^x= xLog a
Log (a/b) = Log a-Log b

Therefore:

2Log x/ Log 2x = Log(x+4)
=
x^2/2x = (x+4)

x^2= (x+4)2x
x^2 = 2x^2*8x

x^2 - 2x^2* = 8x

-(x^2) = 8x
x = -8


Please confirm the answer by substituting x