What is the standard form of the equation of the conic given by 2x^2 + 2y^2 + 4x - 12y - 22 = 0 ?

Question

anonymous · Answer

https://people.richland.edu/james/lecture/m116/conics/conics.html consult the page..:D

anonymous · Answer

Still don't understand

anonymous · Answer

Ax2 + Bxy + Cy2 + Dx + Ey + F = 0

so just take a 2 common from your equation
and then divide both sides of the equation with 2 :D

anonymous · Answer

Can you please walk me through the first steps?

anonymous · Answer

lemme do it for you and sorry for leaving..!
lets take out 2 common
2x^2 + 2y^2 + 4x - 12y - 22 = 0
=> 2 ( x^2 + y^2 + 2x - 6y - 11) = 0
now lets divide both sides with 2 
=>  x^2 + y^2 + 2x - 6y - 11 = 0