Question

What is the standard form of the equation of the conic given by 2x^2 + 2y^2 + 4x - 12y - 22 = 0 ?

Answer 1

https://people.richland.edu/james/lecture/m116/conics/conics.html
consult the page..:D

Answer 2

Still don't understand

Answer 3

Ax2 + Bxy + Cy2 + Dx + Ey + F = 0

so just take a 2 common from your equation
and then divide both sides of the equation with 2 :D

Answer 4

Can you please walk me through the first steps?

Answer 5

lemme do it for you and sorry for leaving..!
lets take out 2 common
2x^2 + 2y^2 + 4x - 12y - 22 = 0
=> 2 ( x^2 + y^2 + 2x - 6y - 11) = 0
now lets divide both sides with 2
=> x^2 + y^2 + 2x - 6y - 11 = 0