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Mathematics 13 Online
OpenStudy (anonymous):

y=cos {inv} [b+acosx/a+bcosx]

myininaya (myininaya):

What are the directions? And does inv represent inverse so you have y=arccos(b+acos(x)/a+bcos(x)) or do we have y=arccos((b+acos(x))/(a+bcos(x))

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