Question

secxcsc^2x=2secx

how to solve equation in the given interval

Answer 1

interval is a set of real numbers with the property that any number that lies between two numbers in the set is also included in the set. For example, the set of all numbers x satisfying 0 ≤ x ≤ 1 is an interval which contains 0 and 1, as well as all numbers between them.

Answer 2

\[\sec x \csc ^2x-2\sec x=0,\sec x \left( \csc ^2x-2 \right)=0\]
\[Either ~\sec x=0,\cos x=\infty ,rejected~as~\left| \cos x \right|\le 1\]

Answer 3

what's the given interval?

Answer 4

oh sorry! 0 less than or equal to x les than 2pi

Answer 5

0<=x<2pi

Answer 6

yes

Answer 7

\[or \csc ^2x=2,\sin ^2x=\frac{ 1 }{2 },2\sin ^2x=1,1-2\sin ^2x=0,\cos 2x=0\]
find x

Answer 8

can you solve?

Answer 9

nope:/

Answer 10

\[\cos 2x=0=\cos \left( 2n+1 \right)\frac{ \pi }{2 },n=0,1,2,3\]
\[2x=\left( 2n+1 \right)\frac{ \pi }{2 },x=?\]

Answer 11

or you can convert each trig ratio to cos and sin
and get and equation in cos x