Question

what is the equation in standard form of the line which passes through (4,-2) and has a slope of -3

Answer 1

First we note the point A(4,-2) then we use "the point-slope formula";
y-yA=m(x-xA)
then we substitute yA=-2;xA=4;m=-3=>y+2=-3(x-4)=>y+2=-3x+12;
and the final form is:
->-3x-y+10=0<-