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sin x + cos x = 0
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What do you want to do with this equation:FIND X? DEMONSTRATE THE EQUALITY..???
Find all solutions for the following trigonometric equations on the interval [0,2pi].
well, lets solve for x. \(\LARGE\color{blue}{ \sf Sin(x)+Cos(x)}\) we know that cos(x)= sqrt [ 1- sin^2x ] \(\LARGE\color{blue}{ \sf Sin(x)+\sqrt{1- Sin^2x} =0}\) subtract Sin(x) from both sides \(\LARGE\color{blue}{ \sf \sqrt{1- Sin^2x} =~-Sin(x)}\) square both sides ( NOTE: (-2)^2=4 not -4 ) \(\LARGE\color{blue}{ \sf 1- Sin^2x =~Sin^2x}\) can you take it from here? @rlave001
Or just do sin(x) = -cos(x) tan(x) = -1 :)
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