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OpenStudy (anonymous):
5+I 1-4 I3-6^2/3 A. 6 B. 11 C. 14 D. 24
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OpenStudy (jdoe0001):
\(\bf 5+|1-4|3-\cfrac{6^2}{3}\implies 5+|1-4|\cdot 3-\cfrac{6^2}{3}\) do the absolute value first, and the exponential, then just continue following PEMDAS -> http://www.mathgoodies.com/images/SS_PEMDAS_Goodies.jpg
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