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find the surface area of the triangular prism. A- 81 in.^2 B- 70.8 in.^2 C- 63 in.^2 D- 78.6 in.^2
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its B
|dw:1396531515848:dw|
its not the best drawing sorry
Hmm seems good enough to me So surface area is going to be \[\large A = bh + 2LS + LB\] L = length B = base H = height S = side length So here we have \[\large A = (3)(2.6) + 2(7)(3) + (7)(3)\] \[\large A = 7.8 + 42 + 21\] \[\large A = 7.8 + 63\] \[\large A = 70.8\]
thank you everyone!
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