plz help: the expression sin(theata+90) is equivalent to?
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OpenStudy (cwrw238):
cos theta
OpenStudy (anonymous):
how do u no tho?
OpenStudy (anonymous):
@AccessDenied canu plz help me
OpenStudy (anonymous):
@cwrw238
OpenStudy (anonymous):
@Koikkara
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OpenStudy (anonymous):
@Kilorion
OpenStudy (anonymous):
@hoblos
OpenStudy (anonymous):
@beccaboo333
OpenStudy (anonymous):
@Loser66
OpenStudy (anonymous):
ok?
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OpenStudy (anonymous):
canu plz explain it more?
OpenStudy (loser66):
no I m sorry, it's cos theta
OpenStudy (anonymous):
canu help me with another ques plz?
OpenStudy (loser66):
sin (a+ b) = sina cos b + sinb cos a
your a = 90 , your b = theta
so that
sin (90 + theta) = sin 90 cos theta + sin theta cos 90
sin 90 =1, cos 90 = 0
so that sin (90+ theta ) = 1* cos theta + sin theta *0= cos theta
OpenStudy (loser66):
I have class right now, cannot help you more. I am sorry, but I can give you the answer if the problem is easy, hurry up
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OpenStudy (anonymous):
: the expression cos4x cos3x+sin4x sin3x is equivalent to?
OpenStudy (loser66):
cos x
because cos (a-b) = cos a cos b + sina sinb
your a is 4x, your b is 3x, so that cos (4x-3x) = cos x