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Find the surface area generated by rotating the given curve about the y-axis. x = 9t^2, y = 6t^3, 0 ≤ t ≤ 1
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I found dx/dt = 18t and dy/dt = 18t^2 I used S = integral from 0 to 1 of (2pi(9t^2)(18t)sqrt(1+t^2))dt
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