Question

Which is an equation of a circle with center (5, 0) that passes through the point (1, 1)?
a.)(x + 5)2 + y2 = 17
b.)(x - 1)2 + (y - 1)2 = 17
c.)(x - 5)2 + y2 = 17
d.)(x + 5)2 + y2 = 24

Answer 1

\[(x-h)^2+(y-k)^2=r^2\]
That is the equation of a circle with center (h,k) and radius r

Answer 2

what would be the h and k?

Answer 3

the center.

Answer 4

Thankyou!

Answer 5

yw

Answer 6

(1-5)^2+(1-0)^2= 17^2
17^2= 289
thats not the right answer. did i do something wrong?

Answer 7

You need to find the radius by using the distance formula to find the distance between the center and (1,1)

Answer 8

ok