Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

√27 + √48 simplify

OpenStudy (anonymous):

\[7\sqrt{3}\]

OpenStudy (anonymous):

howd you get that

OpenStudy (mertsj):

\[\sqrt{27}=\sqrt{9\times 3}=\sqrt{9}\sqrt{3}\] \[\sqrt{48}=\sqrt{16\times 3}=\sqrt{16}\sqrt{3}\] Use those two facts

OpenStudy (anonymous):

7√3 .. √27 9*3 = 3√3 √48 16*3 = 4√3

OpenStudy (anonymous):

27/48 Final result : 9 —— 16 Step by step solution : Step 1 : 9 Simplify —— 16 Final result : 9 —— 16

OpenStudy (mertsj):

\[\sqrt{9}\sqrt{3}=3\sqrt{3}\] \[\sqrt{16}\sqrt{3}=4\sqrt{3}\] \[3\sqrt{3}+4\sqrt{3}=(3+4)\sqrt{3}=7\sqrt{3}\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!