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√27 + √48 simplify
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\[7\sqrt{3}\]
howd you get that
\[\sqrt{27}=\sqrt{9\times 3}=\sqrt{9}\sqrt{3}\] \[\sqrt{48}=\sqrt{16\times 3}=\sqrt{16}\sqrt{3}\] Use those two facts
7√3 .. √27 9*3 = 3√3 √48 16*3 = 4√3
27/48 Final result : 9 —— 16 Step by step solution : Step 1 : 9 Simplify —— 16 Final result : 9 —— 16
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\[\sqrt{9}\sqrt{3}=3\sqrt{3}\] \[\sqrt{16}\sqrt{3}=4\sqrt{3}\] \[3\sqrt{3}+4\sqrt{3}=(3+4)\sqrt{3}=7\sqrt{3}\]
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