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What is the line of symmetry for the graph of y = -3x^2 + 12x - 11? 1.) x=-4 2.) x=-2 3.) x=2
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Isn't that where the vertex is at?
Solving it calculus wise.. \[\large -3x^2+12x-11\] \[\large y'=-6x+12\] \[\large 0=-6x+12\] \[\large x=2\]
It's algebra
Vertex formula \(\large \frac{-b}{2a}\)
So.. \[\LARGE \frac{-12}{2(-3)}=\frac{-12}{-6}=?\]
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2
So x=2 ..?
Yup~
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