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OpenStudy (anonymous):
find the volume of the solid obtained by revolving the region bounded by x=0, y=2, y=x^1/2 about the y-axis
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OpenStudy (anonymous):
|dw:1396581154709:dw| The radius of the 3d wheel would be f(x). The area of a circle is PI*(radius)^2 That's why the total volume is integral along the interval of Pi*(f(x))^2 dx
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