Question

a physical pendulum with rod rotating about an axis through its center. Rod has a uniform mass m1, length L and at one and has mass m2. What's the total moment of inertia

Answer 1

mass at one end is the cylinder, with \[I_c=1/12 m_c x^2+1/4 m_c (r^2+a^2)\] and Inertia of rod is \[I=I_r=1/12*m_r L^2\]

Answer 2

@wolfe8