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1-2sin^2x=0
Solve the equation in the interval 0
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can you find 2 values of sin x first ?
sin x = sqrt(1/2) If you look at the trigonometric table, you will see that sin 45 = sqrt(1/2) Hence 0<x<360 gives you the answers x = 45, (90+45 = 135) pi/4 radians, 3/4 pi radians.
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