Question

Simplify log8 7 - log8 s + log8 t - log8 4

Answer 1

Log8(7/8*8/4)=log8(7/4)

Answer 2

\[\log_b(x)+\log_b(y)=\log_b(xy)\]

\[\log_b(x)-\log_b(y)=\log_b(x/y)\]

Answer 3

7s/4t or would it be 7t/4s. I knew 8 would be the base, it's just the fraction that keeps messing me up

Answer 4

7/s * t/4

use

a/b * c/d = ac/bd

Answer 5

7t/4s is righht

Answer 6

alright, thank you :)

Answer 7

but dont forget the log_8 part

Answer 8

okay, I already had that figured out before I asked