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OpenStudy (anonymous):
Please help me with
1. what is the solution of the system? solve using matrices
{ 7x+2y=-38
{13x-3=32
A. [-54]
[-10]
B. no solution
C. [10]
[54]
D. [-10]
[-54]
12 years ago
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OpenStudy (anonymous):
@hartnn @GamerGirl.1 @grace111 @ganeshie8 @Luigi0210 @hoblos @hello1213 @lyubas @surjithayer @skullpatrol
12 years ago
OpenStudy (anonymous):
im sorry I cant figure this out :(
12 years ago
OpenStudy (anonymous):
its find ill try and figure it out :/
12 years ago
OpenStudy (anonymous):
Do you want to do it using a formula (involving finding the inverse of a matrix) or by reducing an augmented matrix?
12 years ago
OpenStudy (anonymous):
yah i do i just dont understand how to do it
12 years ago
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OpenStudy (anonymous):
We'll do it by row reducing.
Did you forget a y in the second equation?
12 years ago
OpenStudy (anonymous):
yes i did
12 years ago
OpenStudy (anonymous):
ok
12 years ago
OpenStudy (anonymous):
I think i may have figured it out is it [10]
[54]
12 years ago
OpenStudy (anonymous):
That does not satisfy the second equation: \(13x-3y = \begin{cases}13(10)-3(54) = 130 - 112 = 18 \\ 32\end{cases}\)
12 years ago
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OpenStudy (anonymous):
Sorry, it should be
\[13x-3y = \begin{cases}13(10)-3(54) = 130 - 162 = -32 \\ 32\end{cases}\]
Did you forget a -?
12 years ago
OpenStudy (anonymous):
oh i mixed it up
12 years ago
OpenStudy (anonymous):
I guess you are right then. What method did you use?
12 years ago
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