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Find the solution to the system. y=x^2+5x+6 y=4x+12 I'm confused on how you answer this since the second problemhas no A.
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Set it equal to each other and solve \(4x+12=x^2+5x+6\)
Please don't give answers .-.
I can get to -3 and -2 but I need the y's as well and thats where im getting confused.
Why do you need the y's?
My answer choices are (2,20) and (-3,0) (2,20) and (-3,-18) (-2, -20) and (-3, -18) no solutions
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