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How many ways are there to choose a committee of 3 people from a group of 5 people? 10 12 60 70
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\[\left(\begin{matrix}5\\3\end{matrix}\right)\]
The formula for this (choosing 'k' things from a larger set of 'n') is: n! / (k! * (n-k)!) 5! / (3! * 2!) = 5*4* 3! / 3! * 2 = 5 *4 / 2 =10
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