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OCW Scholar - Single Variable Calculus 7 Online
OpenStudy (anonymous):

y=cosh 2x

OpenStudy (phi):

what is the question ?

OpenStudy (anonymous):

Are you finding the derivative? If so, here's how you do it. Given y = cosh2x The derivative of coshx is sinhx So y' = sinh(2x)*2x' Or y' = 2sinh(2x) :)

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