Factor out x^3-27x^6
@hartnn @Callisto @phi
first factor out x^3 from both the terms, what u get ?
actuall thats the wrong equation: its 8x^3-27x^6
still, you'll be able to factor out x^3
x^3(8-27x^3)
yes, 8 is the cube of which number ? 27 is the cube of which number x is the cube of which variable ?
would it be X^3(2-3x)(4+6x+9x^2) and how would I solve this to find the solutions?
thats correct, and why do u need to solve it ? when the question just says to factorize ?
Thats what my teacher wants to to do, she said find the solution
can you solve quadratics ? know the quadratic formula ?
yes so I just solve it using the new equation or original equation?
\( x^3(2-3x)(4+6x+9x^2) = 0 \\ x^3 = 0, \quad x=...? \\ 2-3x= 0, \quad x=...? \\(4+6x+9x^2) = 0, use ~ quadratic formula \)
ok thanks
welcome ^_^
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