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OpenStudy (1645323):
Factor out x^3-27x^6
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OpenStudy (1645323):
@hartnn @Callisto @phi
hartnn (hartnn):
first factor out x^3 from both the terms, what u get ?
OpenStudy (1645323):
actuall thats the wrong equation: its 8x^3-27x^6
hartnn (hartnn):
still, you'll be able to factor out x^3
OpenStudy (1645323):
x^3(8-27x^3)
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hartnn (hartnn):
yes,
8 is the cube of which number ?
27 is the cube of which number
x is the cube of which variable ?
OpenStudy (1645323):
would it be X^3(2-3x)(4+6x+9x^2) and how would I solve this to find the solutions?
hartnn (hartnn):
thats correct, and why do u need to solve it ?
when the question just says to factorize ?
OpenStudy (1645323):
Thats what my teacher wants to to do, she said find the solution
hartnn (hartnn):
can you solve quadratics ?
know the quadratic formula ?
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OpenStudy (1645323):
yes so I just solve it using the new equation or original equation?
hartnn (hartnn):
\( x^3(2-3x)(4+6x+9x^2) = 0 \\ x^3 = 0, \quad x=...? \\ 2-3x= 0, \quad x=...? \\(4+6x+9x^2) = 0, use ~ quadratic formula \)
OpenStudy (1645323):
ok thanks
hartnn (hartnn):
welcome ^_^
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