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Mathematics 8 Online
OpenStudy (anonymous):

x^2-25/x^2-3x-10

OpenStudy (yanasidlinskiy):

\[\frac{ x^2-25 }{ x^2-3x-10 }=\frac{ (x-5)(x+5) }{ (x-5)(x+2) }=\frac{ x+5 }{ x+2 }\]

OpenStudy (anonymous):

Thank you so much Yana!

OpenStudy (yanasidlinskiy):

Your Welcome!!!! No problem!!!! Anytime!:)

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