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y=1/2 sin 2 (x-pi/2)
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so what your asking is\[y= 1/2 \sin (2 \times \pi \div 2)\] right?
thanks
but actually the question is \[y = 1/2 \sin 2 ( x - \pi/2)\]
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y = (1/2) sin 2(x - Pi/2) = [sin (x - Pi/2)*cos (x - Pi/2] We know that: cos (x - Pi/2) = -cos (pi/2 - x) = -sin x. sin (x - Pi/2) = -sin (Pi/2 - x) = -cos x. y = (-cos x)(-sin x) = (1/2)*sin 2x.
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