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find the vertex and the focus of the quadratic
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A) (2, 0), (0, 2) B) (0, 2), (0, 2) C) (0, 0), (0, -2) D) (2, 0), (2,0)
\(x^2 = 4ay\) represents a parabola whose origin is \((0, 0)\)
look at ur options, only one option has origin at (0, 0)
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ok so that would be C) vertex (0,0)
the table is very helpful , I'll save it
you can find out the focus from the table as well : \(x^2 = -8y\) \(y = \frac{1}{4(-2)}x^2\)
that gives \(c = -2\) look at the table, focus = \((0, c) = (0, -2)\)
ok so this is how I can get the y
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yes, always change the equation to one of given forms in the table..
got it, thank you so much @ganeshie8 for your help, again :)
np :)
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