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Part 1: Simplify f(x) 3x^2-4x+1/3x-1 Part 2: Using complete sentences, explain why f(1) = 0, f(0) = -1, and f(-1) = -2, yet f(one-third) is undefined. Be sure to show your work.
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Please don't copy and paste from other sites!! I'm slow and can you show me how you did it and the steps you took! thankyou
Factorize the numerator first
Use whatever quadratic factorization method and you'll get 3x^2-4x+1=(3x-1)(x-1)
And please include parentheses as 3x^2-4x+1/3x-1 is different from (3x^2-4x+1)/(3x-1)
\[\frac{3x^2-4x+1}{3x-1}=\frac{(3x-1)(x-1)}{3x-1}=?\]
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You should be able to calculate the question mark
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