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A coin is tossed 11 times. What is the probability of obtaining exactly 9 heads? A. 0.0269 B. 0.0054 C. 0.1611 D. 0.0806
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\[\Large P=\left(\begin{array}{c}11\\9\end{array}\right)\times\left(\frac12\right)^{11}\]
0.0054 (B)
This is not what I have calculated
Before i got A(0.0269), could that be correct?
11C9 = 55 ½^11 is 1/2048
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Yep I got A
thank you!
no problem
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