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Determine whether BC//DE. AD=15, DB=12, AE=10, and EC=8.
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|dw:1396762546922:dw|
Check if \(\dfrac{AD}{DB}=\dfrac{AE}{EC}\)
ok hold up
shouldn't it be AD/AE=DB/EC
Well they're the same aren't they
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well yeah but i got 120=120
By converse of side splitter theorem, if the line cuts two sides of a triangle proportionally, then it is parallel to the other side
since you got AD/DB = AE/EC, DE must be parallel to BC
so then i did get it right
yup ! good job !!
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