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Mathematics 20 Online
OpenStudy (anonymous):

Y''+5Y'=50x

OpenStudy (anonymous):

The above is to check your answer. Do you know how to proceed to do it?

OpenStudy (cwrw238):

setting y'' + 5y' = 0 auxiliary equation is m^2 - 5m = 0 which has roots m = 0 and m = 5 which gives the general solution c1e^5 + c2e^0 do you know how to continue ?

OpenStudy (cwrw238):

oops sorry i made an error its m^2 + 5m = 0 and general solution is c1e^-5 + c2

OpenStudy (anonymous):

tnx guys :)

OpenStudy (cwrw238):

you now need to find the particular solution

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